решить систему уравнения
2-4y=3(x-2)
2(x+y)=5y+25

2-4y=3(x-2)2(x+y)=5y+2,52 - 4y = 3x - 62x + 2y = 5y + 2.53x + 4y = 8|*32x - 3y = 2.5|*49x + 12y = 24+8x - 12y = 10___________17x = 34x = 34/17x = 2y = (8 - 3x)/4 = (8 - 6)/4 = 2/4 = 0.5Ответ (2; 0.5)