4x²-4x=9x+2
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X-2. X+3. X²+x-6
Решите дробное уравнение

4x²/(x-2)-4x/(x+3)=(9x²+2)/(x-2)(x+3)x²+x-6=0x1+x2=-1 U x1*x2=-6x1=-3 U x2=2ОЗ (x-2)(x+3)≠0⇒x≠2  x≠-34x²(x+3)-4x(x-2)=9x+24x³+12x²-4x²+8x-9x-2=04x³+8x²-x-2=04x²(x+2)-(x+2)=0(x+2)(4x²-1)=0x+2=0x=-24x²-1=04x²=1x²=1/4x=-1/2x=1/2