4ОДЗ x-2>0⇒x>2log(2)[5/(x-2)]>log(2)35/(x-2)>35/(x-2)-3>0(5-3x+6)/(x-2)>0(3x-11)/(x-2)<0x=11/3 x=2 + _ +---------------(2)---------------(11/3)--------------------2<x<11/3 U x>2x∈(2;3 2/3)Ответ х=35ОДЗ x+5>0⇒x>-5√(x+5)=a2a-4/a=72a²-7a-4=0,a≠0D=49+32=81a1=(7-9)/4=-1/2⇒√(x+5)=-1/2 нет решенияa2=(7+9)/4=4⇒√(x+5)=4⇒x+5=16⇒x=116(9/2)^(x-x²)≥(2/9)^(4x+14)x-x²≥-4x-14x²-5x-14≤0x1+x2=5 U x1*x2=-14x1=-2 U x2=7 + _ +-----------------[-2]------------------[7]-------------------x∈[-2;7]