[tex] \left \{ {{x+1 \geq \frac{1}{1-x} } \atop {|x-1|+|x+1| \leq x+2}} ight. [/tex]

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Решим 1(x+1)+1/(x-1)≥0(x²-1+1)/(x-1)(x+1)≥0x²/(x+1)(x-1)≥0x=0  x=1  x=-1           +                  _                 _                   +---------------(-1)------------[0]---------------(1)---------------x<-1U x>1 U x=0x∈(-∞;-1) U (1;∞) U {0}Решим 21)x<-1-x+1-x-1≤x+2x+2x≥-2x≥-2/3нет решения2)-1≤x≤1-x+1+x+1≤x+2x≥00≤x≤13)x>1x-1+x+1≤x+22x-x≤2x≤21<x≤2x∈[0;2]\\\\\\\\\\\                                /////////////////////////   -------(-1)---------[0]----------(1)-----------[2]-----                         \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\Ответ x∈(1;2] U {0}