найдите область определения функции
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y= √ 12-4x-x^2
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1-x

1) 12 - 4x - x² ≥ 0                                    2) 1 - x ≠ 0x² + 4x - 12 ≤ 0                                             x ≠ 1(x + 6)(x - 2) ≤ 0   +                  --                    +____________₀____________       - 6             1             2  x ∈ [- 6 ; 1)∪(1 ; 2]