-x^2+5x(дробная черта) 1-6x + 41x^2-2x(дробная черта) 6x-1
Помогите, срочно, в алгебре 0 ( полное решение без решебника!)

Solve for x over the real numbers:-(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0Multiply both sides by -1:(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0Multiply both sides by (6 x-1) (41 x^2-8 x+1):x (x-5) = 0Split into two equations:x-5 = 0 or x = 0Add 5 to both sides:Answer: x = 5 or x = 0