1)уравнение в задании :√2х - 1 = 3√2х = 3 + 1√2х = 4(√2х)² = 4²2х = 16х = 16/2х = 8-----------------------√(2*8) - 1 = 3√16 - 1 = 34 - 1 = 33 = 3возможный вариант уравнения:√(2х - 1) = 3(√ (2х -1) )² = 3²2х - 1 = 92х = 9 +12х = 10х = 10/2х = 5-----------------------------√(2*5 - 1) = 3√9 = 33 = 32) уравнение в задании:х + 1/х + 5 - х - 2/х - 5 =1 х≠0(х - х) + (1/х - 2/х) + (5 - 5) = 1- 1/х = 1х = - 1---------------------------------------------1 + 1/(-1) + 5 - (-1) - 2/(-1) - 5 = 1- 1 - 1 + 5 + 1 + 2 - 5 = 18 - 7 = 11= 1возможный вариант уравнения:(х+1)/(х +5) - (х-2)/(х-5) = 1 | *(x+5)(x-5)х≠ - 5 ; х≠ 5 (x+1)(x-5) - (x-2)(x+5) = 1*(x+5)(x-5)x² -5x +x - 5 - (x² +5x - 2x -10) = x² - 5²x² -4x - 5 - x² - 3x + 10 =x² - 25-7x + 5 = x² - 25x² - 25 +7x - 5 =0x² +7x - 30 = 0D = 7² - 4*1*(-30) = 49 + 120 = 169 =13² D>0x₁ = ( - 7 - 13)/(2*1) = -20/2 = -10x₂ = ( - 7 +13)/(2*1) = 6/2 = 3проверим:(-10+1)/(-10+5) - (-10-2)/ (-10-5) = -9/(-5) - (-12)/(-15) =1,8 - 0,8 = 1(3 + 1)/(3+5) - (3 - 2)/(3 - 5) = 4/8 - 1/(-2) =0,5 + 0,5 = 1