ПОМОГИТЕ СРОЧНО !!!
1)tg(3x+Pi/4)+1=0

2)2cos(3x/2-Pi/3)=-1

3)2sin x - 1 / 2cos x +√3)=0

tg(3x/2-π/3)=-13x/2-π/3=-π/4+πk3x/2=π/3-π/4+πk3x/2=π/12+πkx=2/3*π/12+2/3*πkx=π/18+2k/32)cos(3x/2-π/3)=-1/23x/2-π/3=±(π-π/3)+2πk3x/2=π/3±2π/3+2πkx=2/3(π/3±2π/3+2πk)