Найдите решения уравнения sin(3x-pi/4)=0 на промежутке [0;pi]

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sin(3x-π/4)=03x-π/4=πk3x=π/4+πkx=π/12+πk/30≤x≤π0≤π/12+πk/3≤π-π/12≤πk/3≤π-π/12-π/12:π/3≤k≤11π/12:π/3-1/4≤k≤11/4k={0;1;2}x1=π/12x2=π/12+π/3=(π+4π)/12=5π/12x3=π/12+2π/3=(π+8π)/12=9π/12=3π/4