y=(x-1)^2(2x+4)^3 найдите f'(x) побыстреееееееее

y = (x - 1)²(2x + 4)³

y' = ((x - 1)²)'* (2x + 4)³ + (x - 1)² * ((2x + 4)³)' = 2(x - 1) * (2x + 4)³ +

+ (x - 1)² * 3(2x + 4)² * (2x + 4)' = 2(x - 1)(2x + 4)³ + 6(x - 1)²(2x + 4)² =

= 2(x - 1)(2x + 4)²(2x + 4 + 3x - 3) = 2(x - 1)(2x + 4)²(5x + 1)