Помогите решить производную сложной функции: f(x)= 3lnx^2 + cos(sinx) - √x- 1 - Znanija.Site

Помогите решить производную сложной функции: f(x)= 3lnx^2 + cos(sinx) - √x- 1
- Предмет:
  Алгебра
- Автор:
  tommycain
- 5 лет назад

Ответы 1

f '(x) = (3lnx² + cos(sinx) - √(x- 1))' = 6x/x² - sin(sinx)·cosx - 1/(2√(x- 1)) = 6/x - sin(sinx)·cosx - 1/(2√(x- 1))
- Автор:
  nakita
- 5 лет назад
- 0
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