помогите решить 2sin^2x-5sinx-3=0
2cos2x-5cosx+2=0

2sin^2 x-5sinx*cosx+3cos^2 x=0 | : Cos²x

2tg²x - 5tgx +3 = 0

tgx = t

2t² - 5t +3 = 0

D = b² -4ac = 25 -24 = 1

t₁ = 6/4 = 1,5                  t₂ = 1

a) tgx = 1,5                 б) tgx = 1

x = arctg1,5 + πk , k ∈Z     x = π/4 + πn , n ∈Z