4) x²+9x-22=0; 2) 3x²-3x+1=0; 8) 3x²+x-2-0. 6) 7x²-11x-6-0; Помогите пожалуйста

Ответ:

To solve the quadratic equation \(x^2 + 9x - 22 = 0\), you can use the quadratic formula:

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

In this equation:

- \(a = 1\)

- \(b = 9\)

- \(c = -22\)

Now, plug these values into the formula and solve for \(x\):

\[x = \frac{-9 \pm \sqrt{9^2 - 4(1)(-22)}}{2(1)}\]

Simplify the equation:

\[x = \frac{-9 \pm \sqrt{81 + 88}}{2}\]

\[x = \frac{-9 \pm \sqrt{169}}{2}\]

Now, take the square root of 169, which is 13:

\[x = \frac{-9 \pm 13}{2}\]

Now, you have two possible solutions:

1. \(x = \frac{-9 + 13}{2} = \frac{4}{2} = 2\)

2. \(x = \frac{-9 - 13}{2