решите уравнение:
1) 3sinX+5cosX= -3;
2) 3√3sinX-5cosX= 7;

1)6sinx/2cosx/2+5cos²x/2-5sin²x/2+3cos²x/2+3sin²x/2=0-2sin²x/2+6sinx/2cosx/2+8cos²x/2=0sin²x/2-3sinx/2cosx/2-4cos²x/2=0  /cos²x/2≠0tg²x/2-3tgx/2-4=0tgx/2=aa²-3a-4=0⇒a1+a2=3 U a1*a2=-4⇒a1=4⇒tgx/2=4⇒x/2=arctg4+πn⇒x=2arctg4+2πna2=-1⇒tgx/2=-1⇒x/2=-π/4+ππn⇒x=-π/2+2πn2)6√3sinx/2cosx/2-5cos²x/2+5sin²x/2-7cos²x/2-7sin²x/2=0-2sin²x/2+6√3sinx/2cosx/2-12cos²x/2=0sin²x/2-3√3sinx/2cosx/2+6cos²x/2=0  /cos²x/2≠0tg²x/2-3√3tgx/2+6=0tgx/2=aa²-3√3a+6=0D=27-24=3a1=(3√3-√3)/2=√3⇒tgx/2=√3⇒x/2=π/3+πn⇒x=2π/3+2πna2=(3√3+√3)/2=2√3⇒tgx/2=2√3⇒x/2=arctg2√3+πn⇒x=2arctg2√3+2πn