Найдите наименьшее значение функции f(x)=4\x+1 На промежутке [0;3] - №6813237

Найдите наименьшее значение функции f(x)=4\x+1 На промежутке [0;3]
- Предмет:
  Алгебра
- Автор:
  wigglesj6du
- 5 лет назад

Ответы 1

y`=-4/(x+1)²≠0y(0)=4/1=4y(3)=4/4=1-наим
- Автор:
  teodosiaavila
- 5 лет назад
- 0
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