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найдите наибольшее и наименьшее значение функции y=1/2x2 на отрезке [-2;1]
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y = 1/[2*(x^2) ] [-2;1]Находим первую производную функции:y' = -1/x3Приравниваем ее к нулю:-1/x3 = 0Глобальных экстремумов нет
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Автор:
karenxhik - 6 лет назад
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