[tex] \frac{8X+3}{7}= \frac{10X-1}{7} [/tex] решите уравнение - №9668691

[tex] \frac{8X+3}{7}= \frac{10X-1}{7} [/tex] решите уравнение
- Предмет:
  Алгебра
- Автор:
  snakeifrp
- 6 лет назад

Ответы 1

$\frac{8x+3}{7} = \frac{10x-1}{7} \\ 8x+3=10x-1 \\ 8x-10x=-1-3 \\ -2x=-4 \\ x=2$ Проверка: $\frac{8*2+3}{7} = \frac{10*2-1}{7} \\ \frac{19}{7} = \frac{19}{7} \\$
- Автор:
  geraldbond
- 6 лет назад
- 0
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I'm in the first year at the university, where I'm studying English. My elder sister, Betty, is studying history at the same university. Betty can organise her time wisely, whereas I do not know what order I should do things in. I find it hard to get up on time, and usually I do not get enough sleep. I have to wind two alarm-clocks to make sure I do not oversleep.

My sister, an early riser, is awake by 7 o'clock, refreshed and full of energy. While I'm wandering round the kitchen, fighting the urge to go back to bed, Уравнения химических реакций my sister manages to have a quick shower, make her bed, put on make up, do her hair, eat a full breakfast and set off to the university. It takes me an hour and a half to get ready. I have a hasty bite and rush out ofthe house. Even if I catch a bus at once I still arrive at the university 15 minutes late, which always makes me feel guilty.

My studies keep me busy all day long. I have 14 hours of English a week. I also have lectures and seminars. At lunchtime I meet up with my sister and we have a snack at the university cafe. After classes I make myself go to the library where I spend about six hours a week reading for my seminars.

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