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Log3 (5-4x)= Log3 (x-1)
Log3 (7-x)>1
log1/3 (3-5x)<-3

log₃ (5 - 4x) = log₃ (x - 1)ОДЗ: 5 - 4x > 0, x < 5/4x - 1 > 0, x > 1 ОДЗ: 1  < x < 5/4, 1 < x < 1,25 5 - 4x = x - 1- 4x - x = - 1 - 5-5x = - 6x = 6/5x = 1,22) log₃ (7 - x) > 1ОДЗ: 7 - x > 0, x < 73 > 17 - x > 3- x > 3 - 7-x > - 4x < 4 x ∈ (- ≈ ; 4)3) log₁/₃ (3 - 5x) < - 30 < 1/3 < 13 - 5x > (1/3)⁻³-5x > 3³ - 3- 5x > 27 - 3- 5x > 24x < - 4,8