При погружении в жидкость на тело объемом 2 дм в кубе действует архимедова сила 14,2Н.Какая это жидкость?
F(архимеда)=V*p*g2дм^3=0.002м^314.2=0.002*10*p14.2=0.02*pp=710кг/м^3 - это вещество БЕНЗИН.
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emiliano972Добавить свой ответ
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