помогите пж срочно!!!!Sin < A =_=_Cos < A=_=_tg < A =_=_ctg< A=_=_ sin < D =_=_Cos < D =_=_ tg < D =_=_ctg < D =_=_​

Ответ:

sinA = CD/AD = 3/5;

cosA = AC/AD = 4/5;

tgA = CD/AC = 3/4;

ctgA = AC/CD = 4/3 = 1 1/3;

sinD = AC/AD = 4/5;;

cosD = CD/AD = 3/5;

tgD = AC/CD = 4/3 = 1 1/3;

ctgD = CD/AC = 3/4.