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угол A равнобедренной трапеции ABCD с основаниями BC и AD равен 47°. Из точки D проведена прямая, которая пересекает прямую BC. в точке K, и CD = DK. Найдите угол CDK.
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Предмет:
Геометрия -
Автор:
beetlereyes - 5 лет назад
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Ответы 1
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угол КСД=47 градусов - накрест лежащие при параллельных прямых АД и ВС и секущей СД, так как СД=КД, то ΔСКД равнобедренный с основанием CК, угол КСД=углуСКД=47 градусов, угол СДК=180-(47+47)=86 градусов
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Автор:
cameron73 - 5 лет назад
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Read the text and mark if the following sentences are
true or false.
Mr. and
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At 10 p.m.
the same evening, to his great relief, his daughter returned home. She could
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The parents did not appreciate the joke as much as their daughter did.
True or
false?
43. Mr. and
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44. They
had a call from their friends.
45. The
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46. Mr.
Barker refused to give the ransom and called the police.
47. The
parents laughed with their daughter at the practical joke.5. Ask 3
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