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К 700г водного раствора этанола с массовой долей 10% добавили 60мл C2H5OH (p= 0,80г/мл). Рассчитайте массу спирта в полученном растворе
Ответы 1
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найдем массу спирта в растворе = 700*10/100=70гпереведем объем спирта в массу = 60мл*0,80г/мл = 48гнайдем массу спирта = 70г+48г =118г
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Автор:
sheba - 5 лет назад
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