m(розч)=200г w1(C12H22O11)=20% m2(розч)=100 г w2(C12H22011)=5% w3 (C12H22011)-? - №29110481

m(розч)=200г
w1(C12H22O11)=20%
m2(розч)=100 г
w2(C12H22011)=5%
w3 (C12H22011)-?
- Предмет:
  Химия
- Автор:
  meggiehumphrey
- 6 лет назад

Ответы 1

12% :-):-):-):-) :-)
- Автор:
  smiley
- 6 лет назад
- 0
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