сколько граммов азотной кислоты содержится в 2 л 20,8%-ного раствора (p=1,12г/мл)?
Дано: Решение:
V(р-ра HNO3)=2 л m(р-ра HNO3)=2*1,12=2,24 г
p(HNO3)=1,12г/мл m(HNO3)=2,24*0,208=0,46592 г
w(HNO3)=20,8%
Найти:
m(HNO3)?
Автор:
ziggy67Добавить свой ответ
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