найдите корень уравнения:
8у-3(2у-3)=7у-2(5у+8)
5(2у-9)+6у=4(3у-2)-21
5у+7(3-у)=3(5-2у)-6
7у-4(3у+5)=2-3(4у-9)

8y-3(2y-3)=7y-2(5y+8)8y-6y+9=7y-10y-168y-6y-7y+10y=-9-165y=-25y=-25:5y=-5Жауабы:y=-52) 5(2y-9)+6y=4(3y-2)-21 10y-45+6y=12y-8-21 10y+6y-12y=45-8-21 4y=16 y=16:4 y=4 Жауабы:y=4 3) 5y+7(3-y)=3(5-2y)-6 5y+21-7y=15-6y-6 5y-7y+6y=-21+15-6 4y=-12 y=12:4 y=3 Жауабы:y=3 4)7y-4(3y+5)=2-3(4y-9) 7y-12y-20=2-12y+27 7y-12y+12y=20+2+27 7y=49 y=49:7 y=7 Жауабы:y=7