1. √(x-1)*√(2x+6)=x+3 решите пожалуйста 2. √(25-20x+4x^2<=1)

√(x - 1) × √(2x + 6) = x + 3(x - 1) × (2x + 6) = (x + 3)²2x² + 6x - 2x - 6 = (x + 3)(x + 3)2x² + 4x - 6 = x² + 3x + 3x + 92x² + 4x - 6 - x² - 6x - 9 = 0x² - 2x - 15 = 0D = b² - 4acD = 4 - 4 × 1 × ( - 15) = 4 + 60 = √64 = 8x₁= 2 + 8/ 2 = 5x₂ = 2 - 8 /2 = - 3Ответ: x₁ = 5, x₂ = - 3