2log²(по основанию 3)(x-1) + 3log(по осн 3)(x-1) + 1 + log(по осн 3)2 <= log(по осн 3)54

ОДЗx-1>0⇒x>1log(3)(x-1)=a2a²+3a+1≤log(3)54-log(3)22a²+3a+1≤log(3)(54/2)2a²+3a+1≤log(3)272a²+3a+1≤32a²+3a+1-3≤02a²+3a-2≤0D=9+16=25a1=(-3-5)/4=-2a2=(-3+5)/4=1/2-2≤a≤1/2-2≤log(3)(x-1)≤1/21/9≤x-1≤√31 1/9≤x≤√3+1x∈[1 1/9;√3+1]