Решите уравнения. А) (Х+3)^2 -2 (х+3)-8=0
Б) 3^х+3^х-3=12

Ax+3=aa²-2a-8=0a1+a2=2 U a1*a2=-8a1=-2⇒x+3=-2⇒x=-5a2=4⇒x+3=4⇒x=1Б3^(x-3)*(27+1)=123^(x-3)*28=123^(x-3)=3/7x-3=log(3)(3/7)x=3+1-log(3)7x=4-log(3)7

х²+6х+9-2х-6-8=0х²+4х-5=0(x+5)(x-1)=0x1=-5  x2=1