8) Прошу. Помогите!

a) sin 2x = [tex] \frac{1}{2} [/tex]
b) 1+2cosx=0

а) sin2x = 1/22x = (-1)^k * π/6 + πk, k∈Zx = (-1)^k * π/12 + πk/2, k∈Zб) 1 + 2cosx = 02cosx = -1cosx = -1/2x = +/- 2π/3 + 2πk, k∈Z