y=8+2x^2-x^4 помогите найти стационарные точки

y=8+2x^2-x^4 помогите найти стационарные точки
- Предмет:
  Математика
- Автор:
  izabelle
- 5 лет назад

Ответы 4

помоги найти с осью х: 8+2x^2-x^4
- Автор:
  anvilp7di
- 5 лет назад
- 0
доп. точки с осью х
- Автор:
  wilkinson
- 5 лет назад
- 0
спс
- Автор:
  sweet tea
- 5 лет назад
- 0
$\huge y=8+2x^2-x^4 \\ y'=4x-4x^3\\ 4x(1-x^2)=0\\ x_1=0, x_2=1, x_3=-1$ Точки пересечения функции с осью Ох: $\huge 8+2x^2-x^4=0\\ t=x^2\\ 8+2t-t^2=0\\ t_1+t_2=2\\ t_1*t_2=-8\\ t_1=-2, t_2=4\\ x^2=4\\ x=\pm 2$
- Автор:
  jayson123
- 5 лет назад
- 0
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y=8+2x^2-x^4 помогите найти стационарные точки

Ответы 4

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