бf(x)=log(3)(tgπ/3)=log(3)√3=1/2гf(x)=cos(sin√(4π²)=cos(sin2π)=cos0=12(4-x²)/(x-1)>0(2-x)(2+x)/(x-1)>0x=2,x=-2,x=1 + _ + _--------------(-2)---------------(1)-------------------(2)--------------------x∈(-∞;-2) U (1;2)3{x+3>0⇒x>-3{log(21)(x+3)≠0⇒x+3≠1⇒x≠1-3⇒x≠-2{(5-x)(5+x)≥0⇒-5≤x≤5 ////////////////////////////////////////////----------[-5]-------(-3)------(-2)----------[5]-------------- \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\x∈(-3;-2) U (-2;5]