(3,8×1,75:10+1,02):100+0,4= - №28176235

(3,8×1,75:10+1,02):100+0,4=
- Предмет:
  Математика
- Автор:
  isiah
- 6 лет назад

Ответы 2

...........................
- Автор:
  finn155
- 6 лет назад
- 0
(3,8 × 1,75 : 10 + 1,02) : 100 + 0,4 =0,41685
1) 3,8 × 1,75 = 6,65
2) 6,65 : 10 = 0,665
3) 1,02 + 0,665 = 1,685
4) 1,685 : 100 = 0,01685
5) 0,01685 + 0,4 = 0,41685
- Автор:
  tripp
- 6 лет назад
- 0
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Два точечных тела с одинаковой массой m каждого подвешены к одной точке на нитях длиной L. сначала нити были разведены и на первое тело помещен заряд q1, а на втором создан избыток в N2 электронов, при этом заряд второго тела стал равен q2. После освобождения тел они притянулись и соприкоснулись, их заряды стали равны q. Затем нити разошлись на угол А, а расстояние между зарядами стало r.

q1нКл = ?
N2 * 1E10 =?
q2 нКл = -112
qнКл = - 46
L = ?
m мг = ?
А град = 44
r см = 44,9
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