Как решить линейное уравнения:
1/3х=12, -4х=1/7, 1/6y=1/3

1)2)3)

1) 1/3 х = 12х = 12/  1/3 = 12* 3/1х = 362) - 4х = 1/7х = 1/7  / (-4) = 1/(7 * (-4)) = - 1/28х = - 1/283) 1/6у = 1/3у = (1/3) / (1/6) = (1/3) / (6/1)у = 2