решите уравнение 5x^2-21x+22=0 . Срочно !

5x²-21x+22 = 0D = b²-4aca = 5; b=-21; c=22D= (-21)²-4*5*22 = 1√D = 1x1 = (-b+√D)/2a = (21+1)/2*5 = 2.2x2 = (-b-√D)/2a = (21-1)/2*5 = 2