определите вид треугольника Авс,если
А (9;3;-5),В(2;10;-5);С(2;3;2)

AB^2=(9-2)^2+(10-3)^2+(-5-(-5))^2=98AB=√98AC^2=(9-2)^2+(3-3)^2+(2-(-5))^2=98AC=√98BC^2=(2-2)^2+(10-3)^2+(2-(-5))^2=98BC=√98AB=AC=BC=√98 => треугольник равносторонний