Система x^2-3y^2=1. x-2y=1

x^2 - 3y^2 = 1 x - 2y = 1х = 1 + 2у(1 + 2у)^2 - 3y^2 = 11^2 + 2*1*2y + (2y)^2 - 3y^2 = 11 + 4y + 4y^2 - 3y^2 = 1приведем подобные:у^2 + 4y = 0y*(y + 4) = 0y1 = 0; y + 4 = 0 y2 = - 4x1 = 1 + 2*0 x2 = 1 + 2*(-4)x1 = 1 x2 = -7Проверка корней:х1 = 1; у1 = 01^2 - 3*0^2 = 11 = 11 - 2*0 = 11 = 1x2 = -7; y2 = -4(-7)^2 - 3*(-4)^2 = 149 - 48 = 11 = 1-7 - 2* (-4) = 1-7 + 8 = 11 = 1Ответ: х1 = 1, у1 = 0; х2 = - 7, у2 = -4