Решите уравнение x^2+2x−15=0.

x^2 + 2x − 15 = 0a=1 b=2 c=-15D = b^2 - 4 * a * сD = 2^2 - 4 * 1 * (-15) = 4 + 4 * 15 = 4 + 60 = 64 = 8^2x1 = (-b + D) / 2ax2 = (-b - D) / 2ax1 = (-2 + 8) / 2*1 = 6 / 2 = 3x2 = (-2 - 8) / 2*1 = -10 / 2 = -5проверка:3^2 + 3*2 - 15 = 09 + 6 - 15 = 00 = 0 верно(-5)^2 + (-5)*2 - 15 = 025 - 10 -15 = 00=0 верноответ: x1 = 3, x2 = -5