Помогите решить плз. 1) ³√256= 2) 1 2/5×√3 4/7= 3) ³√8-37׳√8+37=

1 ) ³ √ 256 = ³ √ ( 16 * 16) = ³ √ ( 4^ 4 ) = ³ √ ( 4 * 4 ^ 3 ) = ³ √4 * ³ √4 ^ 3 = 4 * ³ √4 ;2) 1 целая 2 / 5 × √3 целых 4 / 7 = ( 1 * 5 + 2 ) / 5 * √( 3 * 7 + 4 ) / 7 = ( 5 + 2 ) / 5 * √( 21 + 4 ) / 7 = 7 / 5 * √25/7 = 7 / 5 * 5 /√7 = 7 / √7 = 7 ^ ( 1 - 1 / 2 ) = 7 ^ ( 1 / 2 ) = √7;3) ³√8 - 37 × ³ √8 + 37 = ³√2 ^ 3 - 37 × ³ √2 ^ 3 + 37 = 2 - 37 × 2 + 37 = 2 - 74 + 37 = 2 - 37 = - 35.