1)(x-1)(2x+3)=-2 помогите пожалуйста 2)x^2+7/2=4x

1) (x - 1)(2x + 3) = - 2;2x^2 + 3x - 2x - 3 = - 2;2x^2 + 3x - 2x - 3 + 2 = 0;2x^2 + x - 1 = 0;D = b^2 - 4ac;D = 1^2 - 4 * 2 * (- 1) = 1 + 8 = 9; √D = 3;x = (- b ± √D)/(2a);x1 = (- 1 + 3)/(2 * 2) = 2/4 = 1/2 = 0,5;x2 = (- 1 - 3)/(2 * 2) = - 4/4 = - 1.Ответ. -1; 0,5.2) x^2 + 7/2 = 4x;x^2 + 3,5 = 4x;x^2 - 4x + 3,5 = 0;D = b^2 - 4ac;D = (- 4)^2 - 4 * 1 * 3,5 = 16 - 14 = 2; √D = √2x = (- b ± √D)/(2a);x = (4 ± √2)/2 = 2 ± √2/2 = 2 ± 0,5√2;x1 = 2 + 0,5√2;x2 = 2 - 0,5√2.Ответ. 2 + 0,5√2; 2 - 0,5√2.