Sin2x=0.96. найти sinx

(sin α)^2+(cos α)^2 = 1.Если четверть не указана, то:cos α = √1-(sin α)^2илиcos α =-√1-(sin α)^2.cos 2х = +√(1-0,96^2) = 0,28,cos 2х = -0,28.2(sin α)^2 = 1-cos 2α;sin α = ± √(1-cos 2α)/2.sinx = ±√(1-0.28)/2 = ±√0.72/2 = ±0.6.sinx = ±√(1+0.28)/2 = ±√1,28/2 =±0,8.Ответ. -0,8;-0,6;0,6;0,8.