Помогите пожалуйста !))) Решите уравнение log₅(4+x)+log₅(1+2x)=2log₅3 log₂(1+x)+log₂(2+x)=1 log₂(x-2)+log₂(x+1)=2

1) log₅(4 + x) + log₅(1 + 2 * x) = 2 * log₅3; log₅(4 + x) + log₅(1 + 2 * x) = log₅9; log₅((4 + x)*(1 + 2 * x)) = log₅9; (4 + x) * (1 + 2 * x) = 9;4 + 8 * x + x + 2 * x^2 = 9;2 * x ^ 2 + 9 * x - 5 =0;x = -5;x = 0.5;2) log₂(1+x)+log₂(2+x)=1;log₂(1+x)+log₂(2+x)=log₂ 2;log₂((1+x)*(2+x))=log₂ 2;(1 + x) * (2 + x) = 2;2 + x + 2 * x + x^ 2 - 2 = 0;x^ 2 + 3 * x = 0;x * (x + 3) = 0;x = 0;x = - 3;3) log₂(x-2)+log₂(x+1)=2;log₂(x-2)+log₂(x+1)=log₂ 4;(x - 2) * (x + 1) = 4;x^2 + x - 2 * x - 2 - 4=0;x^ 2 - x - 6 =0 ; x = - 2;x = 3.