Под корнем х+2-под корнем х-6=2

sqrt(х + 2) - sqrt(х - 6) = 2;(x + 2) - 2 * sqrt(x + 2) * sqrt(x - 6) + (x - 6) = 4;2x - 4 - 2 * sqrt(x + 2) * sqrt(x - 6) = 4;2x - 4 -4 = 2 * sqrt(x + 2) * sqrt(x - 6);2x - 8 = 2 * sqrt(x + 2) * sqrt(x - 6);x - 4 = sqrt(x + 2) * sqrt(x - 6);x^2 - 8x + 16 = (x + 2) * (x - 6);x^2 - 8x + 16 = x^2 - 6x + 2x - 12;-8x + 6x - 2x = -16 - 12;-4x = -28;x = -28/-4;x = 7.Ответ: 7.Проверка: sqrt(7 + 2) - sqrt(7 - 6) = 2;sqrt(9) - sqrt(1) = 2;3 - 1 = 2 - верно.