Решите систему уравнений x^2-y^2=24 x-2y=7

x = 2у + 7;(2у + 7)^2 - у^2 = 24;4у^2 + 28у + 49 - у^2 - 24 = 0;3у^2 + 28у + 25 = 0;D  = (28)^2 - 4· 3· 25 = 784 - 300 = 484 = 22^2;y1 = (-28 + 22) / (2 · 3) = -1;y2 = (-28 - 22) / (2 · 3) = -25/3 = -8  1/3;x = 2y + 7;x1 = 2y1 + 7 = 2 · (-1) + 7 = 5;x2 = 2y2 + 7 = 2 · (-25/3) + 7 = (-50 + 21)/3 = -29/3 = -9  2/3;Ответ : (5, -1) и (-9  2/3, -8  1/3);