F(x) = ln 3x-2/3x+2 y''(x=1) = y = e^x/3x y'(x=-1) = y = 3^acrtgx/3 y'= f(x) = lnsin 3x/4 f'(x) =

1) (f(x))\' = (ln( (3x - 2) / (3x + 2)))\' = (3x + 2) / (3x - 2).

 (f(x))\'\' = ((3x + 2) / (3x - 2))\' = (3 * (3x - 2) - 3 * (3x + 2)) / (3x - 2)^2 = -12 / (3x - 2)^2.

  (f(1))\'\' = -12 / (3 - 2)^2 = -12.

2) y\' = (e^x / 3x)\' = (e^x * 3x - 3 * e^x) / (3x)^2 = e^x * (3x - 3) / (3x)^2.

(y(-1))\' = e^(-1) * (3 * (-1) - 3) /(-3)^2 = -2/3 * e^(-1).

3) (y)\' = (3 * arctg(x/3))\' = 3 * 1/3 * 1 / (1 + (x/3)^2 = 1 / (1 + (x/3)^2.

4) y\' = (ln(sin(3/4x))\' = 1/sin(3/4x) * cos(3/4x) * 3/4 = 3/4ctg(3/4x).