РЕШИТЕ КВАДРАТНОЕ УРАВНЕНИЕ t^2-5*10^(-5)t+4*10^(-10)=0

t² - 5*10^-5t + 4*10^-10 = 0

D = (- 5*10^-5)² - 4*4*10^-10 = (-5)²*(10^-5)² - 16*10^-10 = 25*10^-10 - 16*10^-10 = 9*10^-10

√D = √(9*10^-10) = 3*10^-5

t₁ = (5*10^-5 + 3*10^-5)/2 = (8*10^-5)/2 = 4 * 10^-5

t₂ = (5*10^-5 - 3*10^-5)/2 = (2*10^-5)/2 = 10^-5

Ответ: t₁ = 4*10^-5, t₂ = 10^-5