Упростить х(х+y)^2-y(x-y)^2+2y(x^2+y^2) И решить при х+2,5 , у+0,5

х(х + y)^2 - y(x - y)^2 + 2y(x^2 + y^2) = х(х^2 + 2xy + y^2) - y(x^2 - 2xy + y^2) + 2yx^2 + 2y^3 = х^3 + 2x^2y + xy^2 - yx^2 + 2xy^2 + y^3 + 2yx^2 + 2y^3 = х^3 + 2x^2y + xy^2 - x^2y + 2xy^2 + y^3 + 2x^2y + 2y^3 = х^3 + 2x^2y - x^2y + 2x^2y + xy^2 + 2xy^2 + y^3 + 2y^3 = х^3 + x^2y + 2x^2y + 3xy^2 + 3y^3 = х^3 + 3x^2y + 3xy^2 + 3y^3x = 2,5 = 2 5/10 = 2 1/2 = 5/2y = 0,5 = 5/10 = 1/2х^3 + 3x^2y + 3xy^2 + 3y^3 = (5/2)^3 + 3 * (5/2)^2 * (1/2) + 3 * (3/2) * (1/2)^2 + 3 * (1/2)^3 = 125/8 + 3 * 25/4 * 1/2 + 3 * 3/2 * 1/4 + 3 * 1/8 = 125/8 + 75/4 * 1/2 + 9/2 * 1/4 + 3/8 = 125/8 + 75/8 + 9/8 + 3/8 = (125 + 75 + 9 + 3)/8 = (200 + 9 + 3)/8 = (200 + 12)/8 = 212/8 = 106/4 = 53/2 = 26 1/2 = 26 5/10 = 26,5Ответ: 26,5.