Решить уравнение: А)х(5+х)(х-5)-(х-3)(х^2+3х+9)=-23 Б) (2x-3)^2-4(x-1)(x+2)=-2

А) х(5 + х)(х - 5) - (х - 3)(х^2 + 3х + 9) = -23 х(x + 5)(х - 5) - (х - 3)(х^2 + 3х + 3^2) = -23 х(x^2 - 25) - (х^3 - 3^3) = -23 (x^3 - 25x) - (х^3 - 27) = -23 x^3 - 25x - х^3 + 27 = -23 x^3 - х^3 - 25x = -23 - 27-25x = -50x = -50/(-25)x = 2Ответ: 2.Б) (2x - 3)^2 - 4(x - 1)(x + 2) = -2(4x^2 - 12x + 9) - 4(x^2 - x + 2x - 2) = -24x^2 - 12x + 9 - 4(x^2 + x - 2) = -24x^2 - 12x + 9 - 4x^2 - 4x + 8 = -24x^2 - 4x^2 - 12x - 4x + 9 + 8 = -2-16x + 17 = -2-16x = -2 - 17-16x = -19x = -19/(-16)x = 19/16x = 1 3/16Ответ: 1 3/16.