Найдите значение производной функции в точке х0:а) f(x)=e^x x0=ln2б)f(x)=e^3x x0=ln2 в)f(x)=4^x x0=2

a) f(x)\' = (tg^2 (ln x))’ = (ln x)’ * (tg (ln x))’ * (tg^2 (ln x))’ = (ln x)’ * (tg (ln x))’ * (tg^2 (ln x))’ = (1 / х) * (1 / (cos^2 (ln x))) * 2 * (tg (ln x)) = (2tg (ln x)) / x(cos^2 (ln x))).

б) f(x)\' = (e^x – sin (x))’ = (e^x)’ – (sin (x))’ = e^x – cos (x) = e^x – cos (x).

г) f(x)\' = ((5 + 6x)^10 – tg (3x))’ = ((5 + 6x)^10)’ – (tg (3x))’ = (5 + 6x)’ * ((5 + 6x)^10)’ – (tg (3x))’ = ((5)’ + (6x)’) * ((5 + 6x)^10)’ – (3x) * (tg (3x))’ = (0 + 6) * 10 * ((5 + 6x)^9) – 3 * (1 / (cos^2 (3x))) = 6 * 10 * ((5 + 6x)^9) – 3 * (1 / (cos^2 (3x))) = 60 * ((5 + 6x)^9) – (3 / (cos^2 (3x))).