Найдите значение производной функции в точке у = х2 – 5х + 2 в точке х0=-2. Найдите значение производной функции в точке:

1) f(x)\' = (8x^2 – 12x^3 + 6 – 9x)’ = (8x^2)’ – (12x^3)’ + (6)’ – (9x)’ = 8 * 2 * x – 12 * 3 * x^2 + 0 – 9 = 16x – 36x^2 – 9.

2) f(x)\' = (3x - (ln x))’ = (3x)’ - (ln x)’ = 3 * x^(1 – 1) – (1 / x) = 3 * x^(0) – (1 / x) = 3 * 1 – (1 / x) = 3 – (1 / x).

3) f(x)\' = (3x^3 – 5x + 4)’ = (3x^3)’ – (5x)’ + (4)’ = 3 * 3 * x^2 – 5 * 1 + 0 = 9x^2 – 5.

4) f(х)\' = ((3 - 4х)^3)’ = (3 - 4х)’ * ((3 - 4х)^3)’ = ((3)’ – (4х)’) * ((3 - 4х)^3)’ = (0 – 4) * 3 * (3 - 4х)^2 = -4 * 3 * (3 - 4х)^2 = -12 * (3 - 4х)^2 = -12(3 - 4х)^2.