20% liters of 25% salt water mixture is drained and replaced with 28 liters of water What is the percent Salinity of the new mixture A) 21 B) 25 C) 28 D) 20 E) 35​

To solve this problem, we need to use the concept of dilution, which states that the concentration of a solution is proportional to the amount of solute (in this case, salt) present in the solution.The original mixture consists of 25% salt water, which means that 25% of the mixture is salt and the remaining 75% is water. After 20% of the mixture is drained, we are left with 80% of the original mixture.We can represent the original mixture as follows:25% salt + 75% water = 100% mixtureThe mixture that remains after 20% is drained is equal to 80% of the original mixture, or:25% salt + 75% water = 80% mixtureNow, we need to add 28 liters of water to this mixture. This means that the final mixture will be made up of 25% salt, 75% water from the original mixture, and 100% of the water we are adding, for a total of 200%.We can represent the final mixture as follows:25% salt + 75% water + 100% water = 200% mixtureTo find the final concentration of salt in the mixture, we need to divide the amount of salt by the total volume of the mixture and multiply by 100% to express the result as a percentage.The final concentration of salt in the mixture is:(25% / 200%) x 100% = 12.5%Therefore, the correct answer is (A) 21.

the correct answer B)-25%

pls put "the best answer"